Jika diketahui volume balok 1. 296cm² dan perbandingan p:l:t = 3 : 2 : 1, maka luas permukaan balok tersebut adalah. Cm².
![]()
[tex]v = p \times l \times t \\ 1.296 = 3x \times 2x \times x \\ 1.296 = 6 {x}^{3} \\ \frac{1.296}{6} = {x}^{3} \\ x = \sqrt[3]{216} \\ x = 6 \\ \\ p = 3x = 3.6 = 18 \\ l = 2x = 2.6 = 12 \\ t = x = 6 \\ \\ luas \: permukaan \: balok \\ 2(p \times l + p \times t + l \times t) \\ 2(18 \times 12 + 18 \times 6 + 12 \times 6) \\ 2(216 + 108 + 72) \\ 2(396) \\ 792 \: {m}^{2} [/tex]
[answer.2.content]
